Which of the following set of quantum numbers correctly describes an electron in a 5d orbital? A) n = 5, l = 3, ml = +3, ms = +1/2 B) n = 5, l = 2, ml = 0, ms = +1/2 C) n = 5, l = 2, ml = +3, ms = +1/2 D) n = 5, l = 3, ml = +2, ms = +1 E) n = 5, l = 2, ml = +2, ms = +1
Accepted Solution
A:
Answer:B.[tex]n=5, l=2,m_l=0,m_s=+\frac{1}{2}[/tex]Step-by-step explanation:We are given that an electron in a 5d orbitalWe have to find the set of quantum numbers correctly describes an electron in a 5d orbital.We know that n=Principle quantum numberTherefore, n=5Angular momentum quantum number =l=0,1,2,3,..(n-1)l=0 =s-orbital l=1=p- orbitall=2=d=orbital l=3=f orbital Therefore, l=2Magnetic quantum number=[tex]m_l=-l,..,0,..l[/tex][tex]m_l=-2,-1,0,1,2[/tex]5d orbital have only one electron Magnetic quantum number have no fixed valuesTherefore,we can take [tex]m_l=0[/tex]Spin quantum number[tex]m_s=\pm\frac{1}{2}[/tex]5d orbital have only one electron .Then, it has spin-up Therefore, [tex]m_s=+\frac{1}{2}[/tex]Answer:B.[tex]n=5, l=2,m_l=0,m_s=+\frac{1}{2}[/tex]